brighteye3984 brighteye3984
  • 24-05-2023
  • Mathematics
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It can be shown that the algebraic multiplicity of an eigenvalue 1 is always greater than or equal to its geometric multiplicity (that is, the dimension of the corresponding eigenspace). Find h in the matrix A below such that the eigenspace for 1 = 5 is two-dimensional. A = [5 -2 6 -1]
[0 3 h 0]
[0 0 5 4]
[0 0 0 1]

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