Cu(OH)2 has Ksp = 2.2 x 10–20. The complex ion Cu(NH3)42+ has Kf = 2.1 x 1013 . What is the value of the equilibrium constant, K, for the reaction below? Cu(NH3)42+(aq) + 2 OH–(aq) Cu(OH)2(s) + 4 NH3(aq)
A) 1.0 x 10^–33
B) 4.6 x 10^–7
C) 2.1 x 10^13
D) 2.1 x 10^6
E) 9.5 x 10^32