areeshae34 areeshae34

21-04-2024
Mathematics

contestada

If
[tex]y = \sqrt{5 + 2 \\ } [/tex]
Then find
[tex]y + 1 \div y = [/tex]
[tex]y - 1 \div y[/tex]
[tex]y { }^{2} + 1 \div y {}^{2} = [/tex]

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