A square is constructed using the hypotenuse $\overline{ac}$ of right triangle $abc$ as a side, as shown below. find the area of the square if $ab = 5$ and $bc = 9$.
see the picture attached to better understand the problem
we know that Applying the Pythagoras Theorem AC²=AB²+BC²-----> AC²=5²+9²----> AC²=25+81----> AC²=106 AC=√106 units
the length side of the square is equal to the hypotenuse so b=√106 units where b is the length side of the square area of the square=b²-----> (√106)²-----> Area=106 units²
