Respuesta :

calculista
we know that
1+cot ²∅=csc² ∅
cot ∅=4/7
so
1+(4/7)²=csc² ∅
csc² ∅=1+(16/49)
csc² ∅=(65/49)
csc ∅=(√65)/7

remember that
csc ∅=1/sin ∅
sin ∅=1/csc ∅------> sin ∅=7/√65-----> sin ∅=(7√65)/65

the answer is
the best identity to find sin ∅ is
1+cot ²∅=csc² ∅

Answer:

D edge

Step-by-step explanation:

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