The coach of a soccer team is holding tryouts and can only take 3 more players. There are 6 players trying out. How many different groups of 3 players could possibly be chosen?

Respuesta :

[tex] C(6,3)=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20 [/tex]