f(x) = [tex]\sqrt{2 - 9x}[/tex]
2 - 9x ≥ 0
- 9x ≥ - 2
[tex]\frac{-9x}{-9} \geq \frac{-2}{-9}[/tex]
x ≤ [tex]\frac{2}{9}[/tex]
Interval Notation: (-∞, [tex]\frac{2}{9}[/tex]]
