- 8 and 4
These are the terms of a geometric sequence with a common ratio r
r = [tex]\frac{64}{- 128}[/tex] = [tex]\frac{- 32}{64}[/tex] = [tex]\frac{16}{- 32}[/tex] = - [tex]\frac{1}{2}[/tex]
the next 2 terms are obtained by multiplying the previous term by r
16 × - [tex]\frac{1}{2}[/tex] = - 8
- 8 × - [tex]\frac{1}{2}[/tex] = 4
