Answer:
x = 3 and x = 4 → (3, 0) and (4, 0)
Step-by-step explanation:
[tex]\text{x-intercept is for y = 0}.\\\\\text{We have the function:}\ y=x^2-7x+12.\\\\\text{Put y = 0 and calculate the value(s) of x.}\\\\x^2-7x+12=0\\\\x^2-3x-4x+12=0\\\\x(x-3)-4(x-3)=0\\\\(x-3)(x-4)=0\iff x-3=0\ \vee\ x-4=0\\\\x-3=0\qquad\text{add 3 to both sides}\\\boxed{x=3}\\\\x-4=0\qquad\text{add 4 to both sides}\\\boxed{x=4}[/tex]
