meqq33 meqq33
  • 24-04-2019
  • Mathematics
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Write the equation of the circle in general form. Show all of your work.

Write the equation of the circle in general form Show all of your work class=

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PollyP52 PollyP52
  • 23-07-2020

Answer:

x^2 + y^2 + 6x - 8y + 21= 0.

Step-by-step explanation:

The center of this circle is (-3, 4) and the radius id 2.

So in Standard form, the equation is:

(x + 3)^2 + ( y - 4)^2 = 2^2

Converting to General form we have:

x^2 + 6x + 9  + y^2 - 8y + 16 = 4

x^2 + y^2 + 6x - 8y + 9 + 16 - 4 = 0

x^2 + y^2 + 6x - 8y + 21= 0.

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