Respuesta :

Answer:

[tex]-\frac{4}{t^{3}}or -4t^{-3}[/tex]

Step-by-step explanation:

rewrite 2/(t^2) as 2*t^(-2)

[tex](2t^{-2})'=2(t^{-2})'=2*(-2)*t^{-2-1}=-4t^{-3}\\or\\-\frac{4}{t^{3}}[/tex]