For this case we must simplify the following expression:
[tex]\frac {6} {\sqrt {8}}[/tex]
We rewrite 8 as [tex]2 ^ 3 = 2 ^ 2 * 2[/tex]
[tex]\frac {6} {\sqrt {2 ^ 2 * 2}} =\\\frac {6} {2 \sqrt {2}} =\\\frac {3} {\sqrt {2}} =[/tex]
We rationalize, multiplying numerator and denominator by:
[tex]\frac {\sqrt {2}} {\sqrt {2}}\\\frac {3} {\sqrt {2}} * \frac {\sqrt {2}} {\sqrt {2}} =\\\frac {3 \sqrt {2}} {(\sqrt {2}) ^ 2} =\\\frac {3 \sqrt {2}} {2}[/tex]
ANswer:
[tex]\frac {3 \sqrt {2}} {2}[/tex]
