Answer:
x = 5
Step-by-step explanation:
[tex]x^2+11=36\qquad\text{subtract 11 from both sides}\\\\x^2=25\to x=\pm\sqrt{25}\\\\x=-5\ or\ x=5\\============================\\\\\dfrac{x^2-25}{x+5}=0\qquad Domain:\ x+5\neq0\to x\neq-5\\\\\dfrac{x^2-25}{x+5}=0\to x^2-25=0\qquad\text{add 25 to both sides}\\\\x^2=25\to x=-5\notin D\ or\ x=5\in D[/tex]
