Answer:
Peak current = 16.9 A
Explanation:
Given that
RMS voltage = 120 Volts
[tex]V_{rms} = 120 V[/tex]
AC is connected across resistance
[tex]R = 10 ohm[/tex]
now by ohm's law
[tex]V = i R[/tex]
[tex]120 = i (10)[/tex]
[tex]i_{rms} = \frac{120}{10} = 12 A[/tex]
now peak value of current will be given as
[tex]i_{peak} = \sqrt{2} i_{rms}[/tex]
[tex]i_{peak} = \sqrt2 (12) = 16.9 A[/tex]
