Answer:
The de Broglie wavelength of the bacterium is 9.54×10^-19 m
Explanation:
given the mass m 2.27×10^-15 kg of bacterium and the velocity v = 0.306 m/s that it is moving with in the blood. the momentum of the bacterium is P = m×v and the planck constant h = 6.63×10^-34 m^2×kg/s.
the de Broglie wavelength is given by:
λ = h/P
= h/(m×v)
= (6.63×10^-34)/[(2.27×10^-15)×(0.306)]
= 9.54×10^-19 m
Therefore, the de Broglie wavelength of the bacterium is 9.54×10^-19 m .
