We have to find equation of line parallel to 2x-2y = 3 and passes through (7,4)
let equation of line be 2x-2y = k
Let's make it coinciding with (7,4)
2x-2y = k
2(7) - 2(4) = k
14 -8 = k
6 = k
So, Equation of line is 2x-2y = 6
4)We have to find equation of line perpendicular to -6y -4x = 18 and passes through (2,6)
As line is perpendicular,
4y -6 x = k
4(6) -6(2) = k
24 -12 = k
12 = k
So, Equation of line is 4y -6x = 12
