Answer: (3p - 1/6)^3
step-by-step explanation:
27p^3 - 1/216 - 9/2p^2 + 1/4p
= (3p)^3 - (1/6)^3 - 9/2p^2 + 1/4p
= (3p - 1/6)[(3p)^2 + p/2 + 1/36)] - (3p/2)(3p - 1/6)
= (3p - 1/6)(9p^2 + p/2 + 1/36 - 3p/2)
= (3p - 1/6)(9p^2 - 2p/2 + 1/36)
= (3p - 1/6)(9p^2 - p + 1/36)
= (3p - 1/6)(3p - 1/6)(3p - 1/6)
= (3p - 1/6)^3
