amberdavis9858 amberdavis9858
  • 21-10-2019
  • Mathematics
contestada

What would be the first and last terms of the polynomial if it was written in standard form? (x-2)^5 ÷ (x-2)

Respuesta :

aristeus aristeus
  • 23-10-2019

Answer:

In standard form the equation will be [tex]x^4-4x^3+12x^2-16x+16[/tex]

Step-by-step explanation:

We have given polynomial [tex]\frac{(x-2)^5}{(x-2)}[/tex]

After dividing the expression will be [tex](x-2)^4[/tex]

[tex](x-2)^4[/tex] can be written as [tex](x-2)^2\times (x-2)^2[/tex]

[tex](x-2)^2\times (x-2)^2=(x^2+4-4x)(x^2+4-4x)=x^4+4x^2-2x^3+4x^2+16-8x-2x^3-8x+4x^2=x^4-4x^3+12x^2-16x+16[/tex]

So in standard form the equation will be [tex]x^4-4x^3+12x^2-16x+16[/tex]

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