Answer:
The answer to your question is: v = 4.39 m/s
Explanation:
Data
mass = 4.33 Kg
KE = 41.7 J
v = ?
Formula
[tex]KE = \frac{1}{2} mv^{2}[/tex]
[tex]v = \sqrt{\frac{2KE}{m} }[/tex]
[tex]v = \sqrt{\frac{2(41.7)}{4.33} }[/tex]
[tex]v = \sqrt{19.26}[/tex]
v = 4.39 m/s
