You need to isolate/get m by itself in the equation:
3(m + 7) = 6(m + 2) Distribute 3 into (m + 7), and distribute 6 into (m + 2)
(3)m + (3)7 = (6)m + (6)2
3m + 21 = 6m + 12 Subtract 3m on both sides
21 = 3m + 12 Subtract 12 on both sides
9 = 3m Divide 3 on both sides
3 = m
PROOF
3(m + 7) = 6(m + 2)
3(3 + 7) = 6(3 + 2)
3(10) = 6(5)
30 = 30
