Solution:
Given system of equations are:
2x + 3y = 13 ------- eqn 1
4x - y =-2 ------- eqn 2
We can solve by elimination method
Multiply eqn 2 by 3
12x - 3y = -6 ------ eqn 3
Add eqn 1 and eqn 3
2x + 3y = 13
12x - 3y = -6
( - ) ----------------
14x = 7
[tex]x = \frac{7}{14}[/tex]
x = 0.5
Substitute x = 0.5 in eqn 2
4(0.5) - y = -2
2 - y = -2
y = 2 + 2
y = 4
Thus solution is x = 0.5 and y = 4
