Answer:
26,000 J
Explanation:
Heat released when the steam is cooled:
q = mCΔT
q = (10.0 g) (2.02 J/g/K) (100℃ − 110℃)
q = -202 J
Heat released during condensation (gas to liquid):
q = mL
q = (10.0 g) (-2260 J/g)
q = -22,600 J
Heat released when the liquid water is cooled:
q = mCΔT
q = (10.0 g) (4.184 J/g/K) (25℃ − 100℃)
q = -3138 J
Total heat released:
q = -202 J − 22,600 J − 3138 J
q = 25,940 J
Rounded to two significant figures, 26,000 J of heat are released.
