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25-02-2020
Mathematics

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Factorise: 8+(b^2-2)^4-6(b^2-2)^2

Respuesta :

ooblecksrm ooblecksrm

25-02-2020

Answer:

Step-by-step explanation:

Let u = (b^2-2)^2

Now you have 8+u^2-6u = u^2-6u+8

= (u-4)(u-2)

= ((b^2-2)^2-4)((b^2-2)^2-2)

= (b^2-4b)(b^2-4b+2)

= b(b-4)(b-2-[tex]\sqrt{6}[/tex])(b-2+[tex]\sqrt{6}[/tex])

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