KSizzle1998 KSizzle1998

26-02-2020
Mathematics

contestada

Find θ, 0° ≤ θ < 360°, given the following information.
cos θ = [tex]-\frac{\sqrt{3} }{2}[/tex] and θ in QII
θ = ________°

Respuesta :

jimrgrant1 jimrgrant1

26-02-2020

Answer:

Θ = 150°

Step-by-step explanation:

Given

cosΘ = - [tex]\frac{\sqrt{3} }{2}[/tex], then

Θ = [tex]cos^{-1}[/tex] ( - [tex]\frac{\sqrt{3} }{2}[/tex] ) = 150° ← angle in second quadrant

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