Respuesta :

danielmaduroh

Explanation:

We have the function:

[tex]f(x)=\frac{x^2-1}{2x+6}[/tex]

The vertical asymptote can be found when the denominator equal zero, therefore:

[tex]2x+6=0 \\ \\ 2x=-6 \\ \\ x=-3[/tex]

So the vertical asymptote occur at [tex]x=-3[/tex]

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