Respuesta :

sqdancefan

Answer:

  -2/3

Step-by-step explanation:

Put the numbers where the corresponding variables are and do the arithmetic.

  [tex]\dfrac{-c^2+2ac}{c-b}=\dfrac{-(-4)^2+2(-3)(-4)}{-4-8}=\dfrac{-16+24}{-12}\\\\=\dfrac{8}{-12}=\boxed{-\dfrac{2}{3}}[/tex]