pinkflower992009 pinkflower992009

24-03-2020
Chemistry

contestada

A gas under an initial pressure of 0.60 atm is compressed at constant temperature from 27 L to 3.0 L. The final pressure becomes

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oluwashayogunleye oluwashayogunleye

24-03-2020

Answer: 5.4

Explanation:

P2 = P1V1/V2

P2 = (.60atm x 27L) / 3.0L = 5.4atm

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