Answer:
1.9°C
Step-by-step explanation:
Let X be the temperature at noon and -2.5°C be the current temperature after the drop.
-We calculate temperature at noon as:
[tex]\bigtriangleup =t_o-t_n\\4.4=X--2.5\\\\X=4.4-2.5\\\\=1.5\textdegree C[/tex]
Hence, the temperature at noon was 1.9°C
