aluna13 aluna13
  • 25-03-2020
  • Mathematics
contestada

P(x) = 2x² + 1
What is the inverse for p(x)?

Respuesta :

marioyoseph496 marioyoseph496
  • 29-03-2020

Answer:

[tex]P^{-1} (x)=\sqrt{\frac{x-1}{2} }[/tex]

Step-by-step explanation:

1. [tex]P(x)=2x^{2} +1[/tex]

2. [tex]y=2x^{2} +1[/tex]

3.[tex]x=2y^{2} +1[/tex]

4.[tex]2y^{2} =x-1[/tex]

5.[tex]y^{2} =\frac{x-1}{2}[/tex]

6.[tex]y=\sqrt{\frac{x-1}{2} }[/tex]

7.[tex]P^{-1} (x)=\sqrt{\frac{x-1}{2} }[/tex]

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