Answer:
97.5 kJ of heat is required to vaporize 250 g of acetic acid
Explanation:
Acetic acid → CH₃COOH
The heat of vaporization is 23.4 kJ/mol, which it means that 1 mol of acetic releases 23.4 kJ of energy.
Let's convert our mass of acetic to moles:
250 g . 1 mol /60 g = 4.17 moles
Now we propose this rule of three:
1 mol of acetic acid releases 23.4 kJ
Then, 4.17 moles will release (4.17 . 23.4) / 1 = 97.5 kJ
