mulanmike567 mulanmike567
  • 25-03-2020
  • Mathematics
contestada

What is the radius of a sphere with a volume of 5271 m^3, to the nearest tenth of a meter?

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 25-03-2020

Answer:

10.8 m

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

We know the volume is 5271

5271 = 4/3 *3.14 *r^3

5271 = 4.18666666 *r^3

Divide each side by 4.186666666

5271/4.18666666 = r^3

1258.996815 = r^3

Take the cube root of each side

(1258.996815) ^1/3 = (r^3)^1/3

10.7979 = r

To the nearest tenth of a meter

10.8 =r

Answer Link
amberbamber113
amberbamber113 amberbamber113
  • 25-03-2020
R= 10.8m Using the formula V= 4/3 π r3
Solving for R= r=(3V
4π)⅓=(3·5271
4·π)⅓≈10.79613m
Answer Link

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