Answer:
0.459 m.
Explanation:
To calculate the height, use 3rd equation of motion as
[tex]v^2-u^2=2gh[/tex]
Here v is the final velocity, u is the initial velocity, g is the acceleration due to gravity and h is the height.
As ball moving up so acceleration due to gravity becomes negative i.e -g and at maximum height v = 0.
Therefore equation becomes,
[tex]u=\sqrt{2gh}[/tex]
Given u = 3 m/s and g = 9.8 m/s^2.
Substitute the given values, we get
[tex](3m/s)^2=2\times9.8m/s^2h[/tex]
h = 0.459 m
Thus, the height of hill is 0.459 m.
