Respuesta :

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[tex] \sqrt{8} + \sqrt{28} [/tex]
=[tex] \sqrt{4*2} + \sqrt{4*7} [/tex]
=2[tex] \sqrt{2} +2 \sqrt{7} [/tex]
Solutions 

 [tex] \sqrt{8}+ \sqrt{28} Find the number that is multiplied by 4 and is equal to 8 and 28. = \sqrt{4*2} + \sqrt{4*7} \sqrt[2]{2} + \sqrt[2]{7} [/tex]

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