ariidarealist ariidarealist

22-04-2020
Mathematics

contestada

uuuuLITUNCION
Given the function f(x) = -2x2 + 3 over the closed
interval [-1, 2], what are the extreme values?
Minimum:
Maximum:

Respuesta :

ghanami ghanami

22-04-2020

Answer:

Step-by-step explanation:

hello :

f(x) = -2x²+3

in : [-1, 2] f'(x) = - 4x

f'(x) = 0 means : -4x=0 so : x=0

f(0) = -2(0)²+3 = 3 (Maximum:) because : a= -2 and a<0

in : [-1, 0] f is crasing

in : [-1, 2] f is decrasing

Answer Link

ashleyalvarez345 ashleyalvarez345

02-05-2020

Answer:

1.-5

2.3

Step-by-step explanation:

just did it

Answer Link

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