Respuesta :

nktselepov

[tex]\dfrac{x-2}{x-9} =2[/tex]

The denominator can't be equal to 0, so

[tex]x-9\neq 0\\x\neq 9[/tex]

Now we can solve the equation

[tex]\dfrac{x-2}{x-9} =2\\\dfrac{x-2}{x-9}=\dfrac{2x-18}{x-9} \\x-2=2x-18\\-x=-16\\x=16[/tex]

Answer: x=16

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