We just need to put x and y coordinates into equatoins
1)
[tex]y = - \frac{2}{3} x + 1 \\ - 1 = - \frac{2}{3} \times ( - 3) + 1 \\ - 1 \neq3[/tex]
2)
[tex]y = - \frac{2}{3} x + 3 \\ - 1 = - \frac{2}{3} \times ( - 3) + 3 \\ - 1 \neq5[/tex]
3)
[tex]y = - \frac{2}{3} x - 1 \\ - 1 = - \frac{2}{3} \times ( - 3) - 1 \\ - 1 \neq1[/tex]
4)
[tex]y = - \frac{2}{3} x - 3 \\ - 1 = - \frac{2}{3} \times ( - 3) - 3 \\ - 1 = - 1[/tex]
Answer:
[tex]y = - \dfrac{2}{3} x - 3[/tex]
