Answer:
[tex]P=0.583atm[/tex]
Explanation:
Hello,
In this case, by using the ideal gas equation:
[tex]PV=nRT[/tex]
We can compute the pressure as shown below, considering the given data and absolute temperature:
[tex]P=\frac{nRT}{V}=\frac{0.325mol*0.082\frac{atm*L}{mol*K}*(35+273)K}{14.08L}\\ \\P=0.583atm[/tex]
Best regards.
