Answer:
Q(x) = 4
R(x) = 0
Step-by-step explanation:
Q(x) = 2x + 2 ----- (1)
R(x) = x² - 1 -------- (2)
i) For (R * Q)(5) and [(Q * R)], we have as follow:
[(x² - 1)(2x + 2)] (5)
= (2x³ + 2x² - 2x - 2)(5)
= x³ + x² - x - 1
When x = -1
x³ + x² - x - 1 = 0
∴ (x³ + x² - x - 1) ÷ (x + 1) = x² - 1
If x + 1 = 0
x = -1
and x² - 1 = 0
x = 1
From (1), when x= 1: Q(x) = 4
From (2), when x= 1 or -1: R(x) = 0
