Answer:
15i[tex]\sqrt{3}[/tex]
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] and [tex]\sqrt{-1}[/tex] = i
Given
3[tex]\sqrt{-75}[/tex]
= 3 × [tex]\sqrt{25(3)(-1)}[/tex]
= 3 × [tex]\sqrt{25}[/tex] × [tex]\sqrt{3}[/tex] × [tex]\sqrt{-1}[/tex]
= 3 × 5 × [tex]\sqrt{3}[/tex] × i
= 15i[tex]\sqrt{3}[/tex]
