Ackussinglake63 Ackussinglake63
  • 23-08-2020
  • Chemistry
contestada

How many grams of HNO3 is needed to make 1.5 L of a 3 M solution of HNO3?

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sebassandin
sebassandin sebassandin
  • 29-08-2020

Answer:

[tex]m_{HNO_3}=283.5gHNO_3[/tex]

Explanation:

Hello,

In this case, since the molarity is defined in terms of the moles of solute and the volume of solution in liters as follows:

[tex]M=\frac{mol}{V}[/tex]

In such a way, solving for the moles of nitric acid, we obtain:

[tex]mol=M*V=1.5L*3mol/L=4.5molHNO_3[/tex]

Finally, since the molar mass of nitric acid is 63 g/mol, the mass is computed as:

[tex]m_{HNO_3}=4.5molHNO_3*\frac{63gHNO_3}{1molHNO_3} \\\\m_{HNO_3}=283.5gHNO_3[/tex]

Regards.

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