Answer:
Here x=2−3–√ ................…………………………………….....(1)
Hence 12−3√=12−3√⋅2+3√2+3√=2+3–√ .....................(2)
From (1) and (2) we get x+1x=4 .......……………………………....(3)
and x−1x=−23–√ ...............…………………….………....(4)
From (3) and (4) we get x2−1x2=(x+1x).(x−1x)=−83–√.
Hoped I helped
