Jsolages Jsolages
  • 26-08-2020
  • Physics
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1/2mv^2+Fd=mgh solve for F

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Space
Space Space
  • 26-08-2020

Answer:

[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]

Explanation:

Step 1: Write out equation

[tex]\frac{1}{2} mv^2+Fd=mgh[/tex]

Step 2: Subtract FD on both sides

[tex]\frac{1}{2} mv^2=mgh-Fd[/tex]

Step 3: Subtract mgh on both sides

[tex]\frac{1}{2} mv^2-mgh=-Fd[/tex]

Step 4: Divide both sides by -d

[tex]\frac{\frac{1}{2} mv^2-mgh}{-d} =F[/tex]

Step 5: Rewrite

[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]

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