Step-by-step explanation:
It is given that,
Initial speed of the stone, u = 170 ft/s
It is thrown down from a height of 1020 feet.
We need to its height after t seconds. It can be calculated using second equation of kinematics as follows :
[tex]h=ut-\dfrac{1}{2}gt^2+h_0[/tex]
h₀ is initial height, u = -170 ft/s as the stone is throwing down and g = -32ft/s²
Putting values, we get :
[tex]h=-170t-\dfrac{1}{2}\times 32t^2+1020\\\\h=-16t^2-170t+1020[/tex]
