ablera
ablera ablera
  • 23-09-2020
  • Mathematics
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leena
leena leena
  • 23-09-2020

[tex]\text{Hello! :)}[/tex]

[tex]\large\boxed{\frac{84}{15}in^{2}}[/tex]

[tex]\text{Area of a rectangle: A = l * w }\\\\w = 4\frac{1}{5}, \text{ and } l = \frac{4}{3} \\\\\text{Rewrite the mixed number into an improper fraction to make it easier to solve:}\\\\4\frac{1}{5} = \frac{21}{5}\\ \\\text{Multiply the two fractions:}\\\\\frac{21}{5}*\frac{4}{3} = \frac{21*4}{5*3} = \frac{84}{15}in^{2}[/tex]

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