lilliesandlimes
lilliesandlimes
23-09-2016
Mathematics
contestada
I need help on the third question
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Snowflake01
Snowflake01
23-09-2016
For number 3? I think it's 33 because 33x3= 99 and 99+20= 119.
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apologiabiology
apologiabiology
23-09-2016
j+s is no more than 120
j+s≤120
if jacket is 20 more than 3 times skirt
j=20+3s
find max price for each
so we have
j+s≤120 and
j=20+3s
sub 20+3s for j
20+3s+s≤120
20+4s≤120
minus 20 oth sides
4s≤100
divide both sides by 4
s≤25
sub back
if s is 25
j=20+3s
j=20+3(25)
j=20+75
j=95
at most
jacket=$95
skirt=$25
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