Answer:
Maximum height = 1.96 (Approc)
Total time = 1.26 second
Explanation:
Given:
Final velocity v = 6.2 m/s
Find:
Maximum height
Total time
Computation:
v² = u² + 2as
6.2² = 2(9.8)s
S = 1.96 m Approx
Maximum height = 1.96 (Approc)
v = u + at
6.2 = (9.8)(t)
Total time = 0.63 x 2
Total time = 1.26 second
