Answer:
17242,5J
Explanation:
Given parameters:
Mass of water = 75g
Initial temperature = 20°C
Final temperature = 75°C
Unknown:
Amount of heat absorbed = ?
Solution
To find the amount of heat absorbed by water;
H = mcΔt
m is the mass
c is the specific heat capacity of water = 4.18J/g°C
Insert the parameters and solve;
H = 75 x 4.18 x (75 - 20)
H = 17242,5J
