Respuesta :

arslanamir186

Answer:

168 ml

Explanation:

M1V1= M2V2

V1=M2V2/M1

V1= 0.195×15.5/18

V1 = 0.1679 L=168ml

okpalawalter8

Answer:

  • Volume needed to prepare 18.0 M sulfuric acid = [tex]168mL[/tex](Option B)

Explanation:

Given,

[tex]M_1 = 18M\\\\M_2 = 0.195\\\\V_1 = ?\\\\V_2 = 15.5[/tex]

Therefore,

[tex]M_1 * V_1 = M_2 * V_2\\\\ V_1 = \frac{M_2*V_2}{M_1}\\\\V_1 = \frac{0.195*15.5}{18}\\\\V_1 = 0.168L \\\\V_1 = 168mL[/tex]

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