Answer:
[tex]n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2[/tex]
Step-by-step explanation:
[tex]2n^2= 6n - 2\\\\2n^2-6n+2=0\\\\a=2\\\\b=-6\\\\c=2[/tex]
[tex]n=(-b \pm \sqrt{b^2-4ac} )/2a\\\\n=(-(-6) \pm \sqrt{(-6)^2-4(2)(2)} )/2(2)\\\\n=(6 \pm \sqrt{36-16} )/4\\\\n=(6 \pm \sqrt{20} )/4\\\\n=(6 \pm 2\sqrt{5} )/4\\\\n=(3 \pm 1\sqrt{5} )/2\\\\n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2[/tex]
