Answer:
[tex]gf(x))= \frac{10}{\sqrt{x-2} }[/tex]
Step-by-step explanation:
Explanation
Given function f(x) = [tex]1 + \sqrt{x-2}[/tex] and g(x) = [tex]\frac{10}{x-1}[/tex]
gf(x) = ([tex]g(1 + \sqrt{x-2})[/tex] )
[tex]= \frac{10}{1+\sqrt{x-2}-1 }[/tex]
[tex]= \frac{10}{\sqrt{x-2} }[/tex]
[tex]gf(x))= \frac{10}{\sqrt{x-2} }[/tex]
